tag:blogger.com,1999:blog-9207681.post8028981692167041834..comments2024-03-28T10:50:33.234-07:00Comments on Nationals Baseball: Awful Math by Peter KingHarperhttp://www.blogger.com/profile/07738813756060133236noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-9207681.post-29838461750193461812010-03-03T11:49:02.453-08:002010-03-03T11:49:02.453-08:00Anon - that only works if a team can only play 1 O...Anon - that only works if a team can only play 1 OT game per year. <br /><br />Not quite Todd, but on the right track<br /><br />There are (32*16)/2 games in a year or 256 (you can count it if you like) <br /><br />So the chance of ANY SINGLE game being an OT game is 12/256 or 4.6875% <br /><br />The chance of ANY SINGLE game for a single team over the course of a season going to overtime is a bit complicated so instead we figure out the opposite; the chance NO GAMES for a single team over the course of a season goes to overtime. <br /><br />The chance ANY SINGLE game doesn't go to OT is the opposite of the chance is does go to OT or: <br />1-0.048675 = 0.953125.<br /><br />then, the chance all 16 games don't go to OT for a single team in a season is 0.951325 x 0.951325 x 0.951325 x ... 16 times, one for each game. (0.953125 to the 16th, if you prefer) This gets us 0.46387... <br /><br />As we said before, the chance ANY game goes to OT for a single team during the season is the opposite of the chance no games go to OT for a single team during the season or: <br />1-0.46387 or 0.536128.<br /><br />So there iit is<br /><br />53.6% is the answer.Harperhttps://www.blogger.com/profile/07738813756060133236noreply@blogger.comtag:blogger.com,1999:blog-9207681.post-61832504411636171632010-03-03T08:57:41.542-08:002010-03-03T08:57:41.542-08:00You have to figure out how many total games are pl...You have to figure out how many total games are played and what the percentage of those games are OT.<br /><br />32 teams * 16 games in a season =<br />512 games<br />divided by 12 OT games per season =<br />42.6667<br />divided by 16 (since it takes 2 teams to play =<br />2.67% chance of any team playing in an OT game any given sunday <br />and then multiply that 16 times by itself to get the probability of playing in an OT game in a given seasonTodd Lowmanhttp://www.king-cranium-blog.comnoreply@blogger.comtag:blogger.com,1999:blog-9207681.post-55996181532725974412010-03-02T14:48:29.670-08:002010-03-02T14:48:29.670-08:00make that 24/32 = 75%make that 24/32 = 75%Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-9207681.post-13090536006683574582010-03-02T14:47:40.839-08:002010-03-02T14:47:40.839-08:0012 OT games = 24 teams in OT games
24/30 = 75%
W...12 OT games = 24 teams in OT games<br /><br />24/30 = 75%<br /><br />What's the awful math?Anonymousnoreply@blogger.com